Thought I might adjust my rear sight to shoot a bit more to the right. I only moved it .005 inch. I don't know if this will make much of a difference.......................DanielAttachment 35555Attachment 35556Attachment 35557
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Thought I might adjust my rear sight to shoot a bit more to the right. I only moved it .005 inch. I don't know if this will make much of a difference.......................DanielAttachment 35555Attachment 35556Attachment 35557
Probably a little bit. I know that moving the windage on my 24"-barrelled Marlin (Williams peep) will change things about 4" at 100 yards when the sight moves about .020". I expect you're looking at about a 1" change.
You can figure this outQuote:
Originally Posted by Kilo Charlie
Dx at impact = Dx at sight / ( sighting radius/distance to target)
Assuming a 24" sighting radius:
Dx at impact = 0.005 / ( 2/300)
Dx at impact = 0.75"
Or for KC's .020
Dx at impact = 0.020 / ( 2/300)
Dx at impact = 3"
You kill me with your knowledge...Quote:
Originally Posted by werner.reiche
Werner, you are gonna hafta explain you formula a bit more for me. As in sight radius and wtf is Dx?????Quote:
Originally Posted by werner.reiche
Sight radius is the distance between rear and front sights. Generally speaking, longer is more accurate, shorter is faster, so the optimum is to find that sweet spot between too long and too short.
Dx is basically the error/change of poi in relation to the other factors in the equation.
Cheers