Originally Posted by
delmer
Speed alone is not a good indicator of a bows ability to harvest an animal. The question you should be asking is "how much kinetic energy do I need to humanely harvest a deer?" The general answer to that is something around 45 ft/lbs. Kinetic energy is a factor of the speed and weight of the arrow. The amount of KE produced is easily calculated using this formula;
KE = (arrow weight / 450240) x (velocity x velocity)
Usually the advertised fps rating is achieved using the lightest arrow recommended for the bow. For example, a bow that uses a minimum arrow weight of 350 grains achieving 305 fps would have
(350/450240) x (305x305) = 72.3 ft/lbs of kinetic energy
Simple, right?:D